Torthaí beachta
Exact matches
Torthaí gaolmhara
Related matches
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The obligation of proving that the charge laid before the defending party is true
An dualgas atá ann a chruthú gur fíor an cúiseamh atá curtha i leith an pháirtí cosanta
If, when a case is called in Court, the plaintiff appears, and the defendant does not appear, the plaintiff may prove his claim so far as the burden of proof lies upon him
Más rud é, nuair a ghlaofar cás sa Chúirt, go láithreoidh an gearánaí, agus nach láithreoidh an cosantóir, féadfaidh an gearánaí a éileamh a chruthú sa mhéid gur airsean a luífidh an dualgas cruthúnais. FOINSE: I.R. Uimh 510 de 2001
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DRAFT ENTRY
DRÉACHT-IONTRÁIL
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Mathematics » Geometry » Coordinate Geometry Proving a theorem indirectly
Matamaitic » Céimseata » Céimseata Chomhordanáideach Teoirim a chruthú go hindíreach.
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Mathematics » Logic & Set Theory In this method, we assume that the given statement is true and then proceed to derive consequences from it. If we succeed in arriving at a consequence which contradicts a known theorem, we have shown that the given statement is false.
Matamaitic » Loighic & Tacartheoiric Ag úsáid an mhodha seo, glacaimid go bhfuil ráiteas áirithe fíor agus ansin cuirimid chun iarmhairtí a dhíorthú uaidh. Má éiríonn linn teacht ar iarmhairt a dhéanann teoirim aitheanta a bhréagnú, tá sé léirithe againn go bhfuil an ráiteas áirithe bréagach.
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Mathematics » Logic & Set Theory This method is used to disprove statements of the form: for all x in set X, the open sentence p(x) is true. To disprove such an assertion, we proceed to find a counter-example. In other words we look for one value of x for which the statement is false; and since the statement was supposed to be true for all values of x, this single counter example disproves the statement.
Matamaitic » Loighic & Tacartheoiric Úsáidtear an modh seo chun ráitis san fhoirm: do gach x sa tacar X, tá an abairt oscailte p(x) fíor a chruthú. Chun a leithéid de dhearbhú a chruthú, cuirimid chun frithshampla a aimsiú. Is é sin le rá, lorgaímid luach amháin de chuid x dá bhfuil an ráiteas bréagach; agus ó bhí an ráiteas in ainm is a bheith fíor do gach luach de chuid x, cruthaíonn an frithshampla amháin seo an ráiteas a bheith bréagach.